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8x-2x^2+120=0
a = -2; b = 8; c = +120;
Δ = b2-4ac
Δ = 82-4·(-2)·120
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-32}{2*-2}=\frac{-40}{-4} =+10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+32}{2*-2}=\frac{24}{-4} =-6 $
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